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5m^2-18m=0
a = 5; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·5·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*5}=\frac{0}{10} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*5}=\frac{36}{10} =3+3/5 $
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